Math

QuestionBerechne den Flächeninhalt AA des Dreiecks und die gesuchten Längen: a) hah_a, b) hbh_b, c) hch_c, d) hbh_b.

Studdy Solution

STEP 1

Assumptions1. We are dealing with triangles, and the area of a triangle is given by the formula A=1×base×heightA = \frac{1}{} \times base \times height . The base and height are given for each triangle, and we are tasked with finding the area and the missing height.
3. The base and height are perpendicular to each other.

STEP 2

First, let's calculate the area of the first triangle using the given base and height. The formula for the area of a triangle is A=12×base×heightA = \frac{1}{2} \times base \times height.
A=12×c×hcA = \frac{1}{2} \times c \times h_{c}

STEP 3

Now, plug in the given values for the base and height to calculate the area.
A=12×7.2cm×3.5cmA = \frac{1}{2} \times7.2 \, cm \times3.5 \, cm

STEP 4

Calculate the area of the triangle.
A=12×7.2cm×3.cm=12.6cm2A = \frac{1}{2} \times7.2 \, cm \times3. \, cm =12.6 \, cm^{2}

STEP 5

Now, let's find the missing height hah_{a} using the formula for the area of a triangle and the calculated area. The formula for the height is h=2×Abaseh = \frac{2 \times A}{base}.
ha=2×Aah_{a} = \frac{2 \times A}{a}

STEP 6

Plug in the values for the area and the base to calculate the height.
ha=2×12.6cm24cmh_{a} = \frac{2 \times12.6 \, cm^{2}}{4 \, cm}

STEP 7

Calculate the missing height.
ha=2×12.6cm24cm=6.3cmh_{a} = \frac{2 \times12.6 \, cm^{2}}{4 \, cm} =6.3 \, cmRepeat these steps for the remaining parts of the problem, substituting the appropriate values for the base and height in each case.

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