Math  /  Algebra

QuestionZa koji realan parametar bb dani sustav ima jedinstveno rješenje? x1+2x2+(b+1)x3=12x1+bx24x3=0x1+x2+2x3=0\begin{array}{r} x_{1}+2 x_{2}+(b+1) x_{3}=1 \\ -2 x_{1}+b x_{2}-4 x_{3}=0 \\ x_{1}+x_{2}+2 x_{3}=0 \end{array}
Odaberite jedan odgovor: a. b1\quad b \neq 1 i b1b \neq-1 b. b2\quad b \neq 2 i b1b \neq-1 c. b2b \neq 2 i b1b \neq 1 d. Ne znam. e. b2\quad b \neq-2 i b1b \neq 1

Studdy Solution
Identify the correct option based on the values of b b :
The system has a unique solution if b2 b \neq -2 and b1 b \neq 1 .
The correct answer is: e. b2 b \neq -2 and b1 b \neq 1
The correct parameter b b for which the system has a unique solution is given by option e \boxed{e} .

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