Math  /  Geometry

Question原点Oと点P(-3/2, 0)があり、曲線y=36x2y=\frac{\sqrt{3}}{6} x^{2}上の点A, B, Cを求める問題。 (1) A, B, Cの座標 (2) 円の中心座標 (3) Bの接線の式 (4) Bのみが両方にあることを示せ。

Studdy Solution
The only solution is x=Bxx = B_x, which shows that B is the only point on both the graph and the tangent line.

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