Math  /  Data & Statistics

QuestionYou wish to test the following claim (H1)\left(H_{1}\right) at a significance level of α=0.002\alpha=0.002. H0:μ=70.1H1:μ<70.1\begin{array}{l} H_{0}: \mu=70.1 \\ H_{1}: \mu<70.1 \end{array}
You obtain a sample mean of xˉ=68.3\bar{x}=68.3, and sample standard deviation of s=20.4s=20.4 for a sample of size n=45n=45. a. The test statistic (t)(t) for the data == \square (Please show your answer to three decimal places.) b. The pp-value for the sample = \square (Please show your answer to four decimal places.) c. The pp-value is...

Studdy Solution
Compare the p p -value with the significance level α=0.002 \alpha = 0.002 :
Since p=0.2772>0.002 p = 0.2772 > 0.002 , we do not reject the null hypothesis H0 H_0 .
The test statistic t t is:
0.592 \boxed{-0.592}
The p p -value is:
0.2772 \boxed{0.2772}
The p p -value is greater than the significance level, so we do not reject the null hypothesis.

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