Math  /  Data & Statistics

QuestionYou pick a card at random. Without putting the first card back, you pick a second card at random.
What is the probability of picking an odd number and then picking an odd number? Simplify your answer and write it as a fraction or whole number

Studdy Solution
Multiply the probabilities from Step 1 and Step 2:
12×25=210=15 \frac{1}{2} \times \frac{2}{5} = \frac{2}{10} = \frac{1}{5}
The probability of picking an odd number and then picking an odd number is:
15 \boxed{\frac{1}{5}}

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