Math  /  Calculus

Questionln2x+2lnx1xdx\int \frac{\ln ^{2} x+2 \ln x-1}{x} d x

Studdy Solution
Substitute back u=lnx u = \ln x into the integrated expression:
(lnx)33+(lnx)2lnx+C\frac{(\ln x)^3}{3} + (\ln x)^2 - \ln x + C
The solution to the integral is:
(lnx)33+(lnx)2lnx+C\boxed{\frac{(\ln x)^3}{3} + (\ln x)^2 - \ln x + C}

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