Math  /  Algebra

Question23x+112\frac{2}{3 x+1} \geq \frac{1}{2}

Studdy Solution
Consideriamo il dominio della frazione originale, 3x+10 3x + 1 \neq 0 , quindi x13 x \neq -\frac{1}{3} .
L'intervallo di valori per x x che soddisfa la disuguaglianza è:
x1ex13x \leq 1 \quad \text{e} \quad x \neq -\frac{1}{3}
La soluzione è:
x(,13)(13,1]x \in (-\infty, -\frac{1}{3}) \cup (-\frac{1}{3}, 1]

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