Question$\int_{1}^{e^{2}} \frac{\ln p}{p} d p$

Studdy Solution
Evaluate the definite integral from $0$ to $2$:
$$\left[ \frac{u^2}{2} \right]_{0}^{2} = \frac{2^2}{2} - \frac{0^2}{2}$$
$$= \frac{4}{2} - 0$$
$$= 2$$
The value of the definite integral is:
$$\boxed{2}$$