Math  /  Calculus

Question\int \frac{1}{x^2} \, dx

Studdy Solution
Add the constant of integration CC:
1x2dx=1x+C\int \frac{1}{x^2} \, dx = -\frac{1}{x} + C
The integral of 1x2\frac{1}{x^2} is:
1x+C-\frac{1}{x} + C

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