QuestionExpress $\tan \left(\beta+25^{\circ}\right)$ using its cofunction for acute angles.

Studdy Solution
implify the expression inside the parentheses on the right side of the equation.
$$\tan \left(\beta+25^{\circ}\right) = \cot\left(65^{\circ} - \beta\right)$$So, the function $\tan \left(\beta+25^{\circ}\right)$ can be written as $\cot\left(65^{\circ} - \beta\right)$ in terms of its cofunction.