Math  /  Word Problems

QuestionWrite the nuclear equation for beta decay of 82210 Pb{ }_{82}^{210} \mathrm{~Pb}. Options include:
1. 82210 Pb210β+84210Po{ }_{82}^{210} \mathrm{~Pb} \rightarrow{ }^{2}{ }_{-1}^{0} \beta+{ }_{84}^{210} \mathrm{Po}
2. None of these
3. 82210 Pb+10β81210Tl{ }_{82}^{210} \mathrm{~Pb}+{ }_{-1}^{0} \beta \longrightarrow{ }_{81}^{210} \mathrm{Tl}
4. 82210 Pb10β+84210At{ }_{82}^{210} \mathrm{~Pb} \rightarrow{ }_{-1}^{0} \beta+{ }_{84}^{210} \mathrm{At}
5. 82210 Pb24β+2010Hg{ }_{82}^{210} \mathrm{~Pb} \rightarrow{ }_{2}^{4} \beta+{ }^{2010} \mathrm{Hg}
6. 82210pb0β+210pi{ }_{82}^{210} \mathrm{pb} \longrightarrow{ }^{0} \beta+{ }^{210} \mathrm{p} i
7. 210 Pb,110+210811{ }^{210} \mathrm{~Pb}, \frac{110+210}{811}

Studdy Solution
However, the options provided in the problem do not include Bismuth (Bi). This suggests that there might be an error in the problem statement or the options. The correct nuclear equation for the beta decay of 82210 b{ }_{82}^{210} \mathrm{~b} should be82210b83210Bi+10β^{210}_{82}\mathrm{b} \rightarrow^{210}_{83}\mathrm{Bi} + { }_{-1}^{0} \beta

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