QuestionExpress $\sin(t) \sec(t)$ using $\sin t$ and $\cos t$, then simplify.

Studdy Solution
implify the expression by multiplying $\sin t$ with $\frac{1}{\cos t}$.
$$\sin (t) \cdot \frac{1}{\cos t} = \frac{\sin t}{\cos t}$$The expression $\sin (t) \sec (t)$ simplifies to $\frac{\sin t}{\cos t}$ in terms of $\sin t$ and $\cos t$.