Math  /  Algebra

QuestionWrite an expression to describe the sequence below. Use nn to represent the position of a term in the sequence, where n=1n=1 for the first term. 6,12,18,24,an=\begin{array}{l} -6,-12,-18,-24, \ldots \\ a_{n}=\square \end{array}

Studdy Solution
Substitute the values of a1a_1 and dd into the general formula.
an=6+(n1)(6) a_n = -6 + (n-1)(-6)
Simplify the expression: an=66(n1) a_n = -6 - 6(n-1) an=66n+6 a_n = -6 - 6n + 6 an=6n a_n = -6n
The general term of the sequence is: an=6n a_n = -6n

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