Math  /  Algebra

Question Find the recursive rule for the sequence 4,12,36,108,4, -12, 36, -108, \ldots.

Studdy Solution
The first term of the sequence is4, so we can write the complete recursive rule asTerm1=4Term_{1} =4Termn=Termn1×3,forn>1Term_{n} = Term_{n-1} \times -3, \, for \, n >1So, the recursive rule for the sequence 4,12,36,108,4,-12,36,-108, \ldots is Term1=4Term_{1} =4 and Termn=Termn1×3Term_{n} = Term_{n-1} \times -3 for n>1n >1.

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