QuestionWrite $66^{2}$ as a product of its prime factors in index form.

Studdy Solution
Express $66^2$ as a product of its prime factors in index form.
Since $66 = 2 \times 3 \times 11$, then:
$$66^2 = (2 \times 3 \times 11)^2$$
Apply the power of a product rule:
$$(2 \times 3 \times 11)^2 = 2^2 \times 3^2 \times 11^2$$
The prime factorization of $66^2$ in index form is:
$\boxed{2^2 \times 3^2 \times 11^2}$