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QuestionWhich statement is correct? (2.06×10−2)(1.88×10−1)<7.69×10−22.3×10−5\left(2.06 \times 10^{-2}\right)\left(1.88 \times 10^{-1}\right)<\frac{7.69 \times 10^{-2}}{2.3 \times 10^{-5}} (2.06×10−2)(1.88×10−1)≥7.69×10−22.3×10−5\left(2.06 \times 10^{-2}\right)\left(1.88 \times 10^{-1}\right) \geq \frac{7.69 \times 10^{-2}}{2.3 \times 10^{-5}} (2.06×10−2)(1.88×10−1)>7.69×10−22.3×10−5\left(2.06 \times 10^{-2}\right)\left(1.88 \times 10^{-1}\right)>\frac{7.69 \times 10^{-2}}{2.3 \times 10^{-5}} (2.06×10−2)(1.88×10−1)=7.69×10−22.3×10−5\left(2.06 \times 10^{-2}\right)\left(1.88 \times 10^{-1}\right)=\frac{7.69 \times 10^{-2}}{2.3 \times 10^{-5}}

Studdy Solution
The correct statement is (2.06⋅10−2)(1.88⋅10−1)<7.69⋅10−22.3⋅10−5(2.06 \cdot 10^{-2})(1.88 \cdot 10^{-1}) < \frac{7.69 \cdot 10^{-2}}{2.3 \cdot 10^{-5}}.

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