Math  /  Word Problems

QuestionWhich option has the most moles of oxygen atoms: A) 1 mol1 \mathrm{~mol} of Fe(C2H3O2)3\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{3}, B) 1 mol1 \mathrm{~mol} of Na3PO4\mathrm{Na}_{3} \mathrm{PO}_{4}, C) 2 mol2 \mathrm{~mol} of Ca(NO2)2\mathrm{Ca}\left(\mathrm{NO}_{2}\right)_{2}, or D) 3 mol3 \mathrm{~mol} of CH3OH\mathrm{CH}_{3} \mathrm{OH}?

Studdy Solution
Now, we compare the moles of oxygen atoms in each compound. The compound with the most moles of oxygen atoms is Ca(NO2)2\mathrm{Ca}\left(\mathrm{NO}_{2}\right)_{2} with8 moles of oxygen atoms.
The answer is C) 2 mol2 \mathrm{~mol} of Ca(NO2)2\mathrm{Ca}\left(\mathrm{NO}_{2}\right)_{2}.

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