Math  /  Discrete

QuestionWhich of the following arguments is not valid? ¬(pq)¬q\frac{\neg(p \rightarrow q)}{\therefore \neg q} pqpq\frac{p}{q} \begin{array}{l}\therefore p \leftrightarrow q\end{array} pqp \vee q pq\frac{p}{\therefore q} pqp \leftrightarrow q pqp\frac{p \vee q}{\therefore p}

Studdy Solution
Evaluate the argument pqp\frac{p \vee q}{\therefore p}.
- The premise is pqp \vee q. - The conclusion is pp. - From pqp \vee q, we cannot conclude pp without knowing the truth value of qq. - This argument is not valid.
The arguments that are not valid are:
1. pqpq\frac{p}{q} \begin{array}{l}\therefore p \leftrightarrow q\end{array}
2. pq\frac{p}{\therefore q}
3. pqp\frac{p \vee q}{\therefore p}

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