Math  /  Data & Statistics

QuestionWhen a solid dissolves in water, heat may be evolved or absorbed. The heat of dissolution (dissolving) can be determined using a coffee cup calorimeter.
In the laboratory a general chemistry student finds that when 3.68g\mathbf{3 . 6 8} \mathrm{g} of NH4Cl( s)\mathbf{N H}_{4} \mathbf{C l}(\mathrm{~s}) are dissolved in 109.60 g of \mathbf{1 0 9 . 6 0 ~ g ~ o f ~} water, the temperature of the solution drops from 22.47 to 20.09C20.09^{\circ} \mathrm{C}.
The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.84 J/C1.84 \mathrm{~J} /{ }^{\circ} \mathrm{C}.
Based on he student's observatic calculate the enthalpy of dissolution of NH4Cl( s)\mathbf{N H}_{4} \mathbf{C l}(\mathrm{~s}) in kJ/mol\mathrm{kJ} / \mathrm{mol}.
Assume the specific heat of the solution is equal to the specific heat of water. ΔHdissolution =\Delta H_{\text {dissolution }}= \square kJ/mol\mathrm{kJ} / \mathrm{mol}

Studdy Solution
The enthalpy of dissolution of NH4Cl(s)NH_4Cl(s) is 15.80kJ/mol\mathbf{15.80 \, kJ/mol}.

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