Math  /  Algebra

QuestionWhat function results from horizontally stretching y=xy=\sqrt{x} and reflecting it in the xx-axis? Options are:
1. y=2xy=-\sqrt{2 x}
2. y=12(x)y=\sqrt{\frac{1}{2}(-x)}
3. y=2(x)y=\sqrt{2(-x)}
4. y=12xy=-\sqrt{\frac{1}{2} x}

Studdy Solution
Finally, let's consider the last optiony=12xy=-\sqrt{\frac{1}{2}x}This function represents a horizontal stretch by a factor of2 and a reflection in the xx-axis, which matches our derived function from step3. Therefore, this is the correct answer.
The function produced by a horizontal stretch of the graph of y=xy=\sqrt{x} followed by a reflection in the xx-axis is y=12xy=-\sqrt{\frac{1}{2}x}.

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