Math  /  Calculus

QuestionWe wish to find the length of the shortest ladder that will reach from the ground over the fence to the wall of the building. [A] First, find a formula for the length of the ladder in terms of θ\theta. (Hint: split the ladder into 2 parts.) Type theta for θ\theta. L(θ)=15sin(θ)+5cos(θ)L(\theta)=\frac{15}{\sin (\theta)}+\frac{5}{\cos (\theta)} [B] Now, find the derivative, L(θ)L^{\prime}(\theta). Type theta for θ\theta. L(θ)=15cos(θ)sin2(θ)+5sin(θ)cos2(θ)L^{\prime}(\theta)=-\frac{15 \cos (\theta)}{\sin ^{2}(\theta)}+\frac{5 \sin (\theta)}{\cos ^{2}(\theta)} [C] Once you find the value of θ\theta that makes L(θ)=0L^{\prime}(\theta)=0, substitute that into your original function to find the length of the shortest ladder. (Give your answer accurate to 5 decimal places.) L(θmin)1 feet L\left(\theta_{\min }\right) \approx 1 \text { feet } \square Enter an integer or decimal number [more.-1] Submit Question

Studdy Solution
The shortest ladder length is approximately **27.14328** feet (rounded to 5 decimal places).

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