QuestionUsing the quadratic formula to solve $x^{2}+20=2 x$ , what are the values of $x$ ? $1 \pm \sqrt{21}$ i $-1 \pm \sqrt{19} i$ $1 \pm 2 \sqrt{19} ;$ $1 \pm \sqrt{19} i$

Studdy Solution
The solutions to the equation $x^2 + 20 = 2x$ are $x = 1 + \sqrt{19}i$ and $x = 1 - \sqrt{19}i$ .

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