Math  /  Trigonometry

QuestionUsing the Law of Sines to solve the triangle if A=39,C=69,b=25\angle A=39^{\circ}, \angle C=69^{\circ}, b=25 : B\angle B is \square degrees; a=a= \square ; c=c= \square ; You may round to two decimal places. Assume A\angle A is opposite side a,Ba, \angle B is opposite side bb, and C\angle C is opposite side cc.

Studdy Solution
Use the Law of Sines to find side cc:
csinC=bsinB\frac{c}{\sin C} = \frac{b}{\sin B} c=bsinCsinBc = \frac{b \cdot \sin C}{\sin B} Substitute the known values: c=25sin69sin72c = \frac{25 \cdot \sin 69^\circ}{\sin 72^\circ}
Calculate using a calculator: c250.93360.951124.55c \approx \frac{25 \cdot 0.9336}{0.9511} \approx 24.55
The values are: B=72,a16.54,c24.55\angle B = 72^\circ, \quad a \approx 16.54, \quad c \approx 24.55

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord