Math  /  Algebra

Question4. [-/0.32 Points]
DETAILS MY NOTES SCOLALG7 4.4.014. 0/100 Submissions
Use the Laws of Logarithms to evaluate the expression. 13log5(125)-\frac{1}{3} \log _{5}(125) \square Need Helo?

Studdy Solution
Substitute back into the original expression and simplify:
13log5(125)=133=1 -\frac{1}{3} \log_5(125) = -\frac{1}{3} \cdot 3 = -1
The evaluated expression is:
1 \boxed{-1}

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