Math / AlgebraQuestionEvaluate (f∘g)(6)(f \circ g)(6)(f∘g)(6) for f(x)=x+28f(x)=\sqrt{x+28}f(x)=x+28 and g(x)=x2g(x)=x^{2}g(x)=x2. What is the simplified result?Studdy Solutionimplify the square root.f(36)=64=8 f(36) = \sqrt{64} =8 f(36)=64=8So, the value of (f∘g)(6)(f \circ g)(6)(f∘g)(6) is8. View Full Solution - FreeWas this helpful?