Math  /  Calculus

Question- It will be turned in automatically after the due date. 10. Submit answer Practice similar
Use a change of variables to evaluate the definite integral 01(2x1x2)dx\int_{0}^{1}\left(2 x \sqrt{1-x^{2}}\right) d x. Leave your final answer as a fraction. 01(2x1x2)dx=\int_{0}^{1}\left(2 x \sqrt{1-x^{2}}\right) d x= \square

Studdy Solution
Combine the results: =1+0=1 = 1 + 0 = 1
The value of the definite integral is:
1 \boxed{1}

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