Math  /  Algebra

QuestionTwo pools are being filled with water. To start, the first pool contains 784 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 18.25 liters per minute. Water is being added to the second pool at a rate of 42.75 liters per minute.
After how many minutes will the two pools have the same amount of water? \square minutes
How much water will be in each pool when they have the same amount? \square titers

Studdy Solution
Calculate the amount of water in each pool at that time.
Substitute t=32 t = 32 back into either equation for the amount of water:
Using the first pool's equation: W1(32)=784+18.25×32 W_1(32) = 784 + 18.25 \times 32
Calculate: W1(32)=784+584=1368 W_1(32) = 784 + 584 = 1368
Thus, when the pools have the same amount of water, each pool contains: 1368 \boxed{1368} liters

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