Math  /  Geometry

QuestionThe vertices of triangle PQRP Q R are P(6,4),Q(6,2)P(-6,-4), Q(6,2), and R(2,8)R(-2,8). Line segment PQP Q can be defined by the equation: x2y2=0x-2 y-2=0 x3y2=0x-3 y-2=0 y=12x+1y=\frac{1}{2} x+1 y=13x2y=\frac{1}{3} x-2

Studdy Solution
Compare the derived equation y=12x1 y = \frac{1}{2}x - 1 with the given options:
1. x2y2=0 x - 2y - 2 = 0
2. x3y2=0 x - 3y - 2 = 0
3. y=12x+1 y = \frac{1}{2}x + 1
4. y=13x2 y = \frac{1}{3}x - 2

The correct equation for line segment PQ PQ is not directly listed among the options. However, the closest match based on slope is option 3: y=12x+1 y = \frac{1}{2}x + 1 , but it does not match the y-intercept.
The equation of line segment PQ PQ is:
y=12x1 y = \frac{1}{2}x - 1

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