Math  /  Calculus

QuestionThe velocity v(t)v(t) in the table below is increasing for 0t120 \leq t \leq 12. \begin{tabular}{|c|c|c|c|c|c|} \hlinett & 0 & 3 & 6 & 9 & 12 \\ \hlinev(t)v(t) & 32 & 36 & 39 & 40 & 44 \\ \hline \end{tabular} A. Find an upper estimate for the total distance traveled using n=4n=4 subdivisions: distance traveled = \square n=2n=2 subdivisions: distance traveled = \square B. Which of the two answers in part (A) is more accurate? n=n= \square is more accurate (Be sure that you can explain why!) C. Find a lower estimate for the total distance traveled using n=4n=4. distance traveled == \square

Studdy Solution
For the lower estimate using n=4 n=4 subdivisions, use the Left Endpoint method:
Lower Estimate=v(0)3+v(3)3+v(6)3+v(9)3\text{Lower Estimate} = v(0) \cdot 3 + v(3) \cdot 3 + v(6) \cdot 3 + v(9) \cdot 3 =323+363+393+403= 32 \cdot 3 + 36 \cdot 3 + 39 \cdot 3 + 40 \cdot 3 =96+108+117+120=441= 96 + 108 + 117 + 120 = 441
The solutions are: A. Upper estimate for n=4 n=4 : 477 477 Upper estimate for n=2 n=2 : 498 498 B. n=4 n=4 is more accurate. C. Lower estimate for n=4 n=4 : 441 441

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