Math  /  Calculus

QuestionThe velocity function is v(t)=t2+6t8v(t)=-t^{2}+6 t-8 for a particle moving along a line. Find the displacement and the distance traveled by the particle during the time interval [-2,6]. displacement = 120.67-120.67 \square distance traveled = 92.67 \square

Studdy Solution
The displacement is 128/342.67-128/3 \approx -42.67.
The distance traveled is 172/357.33172/3 \approx 57.33.

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