Math  /  Algebra

QuestionThe table represents a linear function. The rate of change between the points (5,10)(-5,10) and (4,5)(-4,5) is -5 . What is the rate of change between the points (3,0)(-3,0) and (2,5)(-2,-5) ? \begin{tabular}{|c|c|} \hlinexx & yy \\ \hline-5 & 10 \\ \hline-4 & 5 \\ \hline-3 & 0 \\ \hline-2 & -5 \\ \hline \hline \end{tabular} 5-5 15-\frac{1}{5} 15\frac{1}{5} 5 Mark this and return Save and Exit Next Submit

Studdy Solution
Calculate the rate of change between the points (3,0)(-3, 0) and (2,5)(-2, -5):
m=502(3)=51=5m = \frac{-5 - 0}{-2 - (-3)} = \frac{-5}{1} = -5
The rate of change between the points (3,0)(-3, 0) and (2,5)(-2, -5) is 5-5.
5\boxed{-5}

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