Math  /  Data & Statistics

QuestionThe table gives a set of outcomes and their probabilities. Let AA be the event "the outcome is divisible by 33^{\prime \prime}. Find P(A)P(A). \begin{tabular}{|c|c|} \hline Outcome & Probability \\ \hline 1 & 0.11 \\ \hline 2 & 0.14 \\ \hline 3 & 0.03 \\ \hline 4 & 0.16 \\ \hline 5 & 0.05 \\ \hline 6 & 0.09 \\ \hline 7 & 0.19 \\ \hline 8 & 0.23 \\ \hline \end{tabular} \square

Studdy Solution
The probability of the outcome being divisible by 33 is 0.120.12.

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