Math  /  Data & Statistics

QuestionThe table gives a set of outcomes and their probabilities. Let AA be the event "the outcome is divisible by 2"2 ". Let BB be the event "the outcome is prime". Find P(AB)P(A \mid B). \begin{tabular}{|c|c|} \hline Outcome & Probability \\ \hline 1 & 0.3 \\ \hline 2 & 0.4 \\ \hline 3 & 0.1 \\ \hline 4 & 0.2 \\ \hline \end{tabular} \square

Studdy Solution
P(AB)=0.8P(A \mid B) = 0.8.
There's an **80% chance** that the outcome is divisible by 22 given that it's prime!

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