Math  /  Calculus

Question\begin{tabular}{|l|l|} \hlinef(3)=3f(3)=3 & limx3f(x)=2\lim _{x \rightarrow 3} f(x)=2 \\ \hlineg(3)=8g(3)=8 & limx3g(x)=8\lim _{x \rightarrow 3} g(x)=8 \\ \hlineh(3)=4h(3)=4 & limx3h(x)=2\lim _{x \rightarrow 3} h(x)=2 \\ \hline \end{tabular}
The table above gives selected values and limits of the functions f,gf, g, and hh. What is limx3(h(x)(2f(x)+3g(x)))?\lim _{x \rightarrow 3}(h(x)(2 f(x)+3 g(x))) ?

Studdy Solution
Substitute the limit of h(x)h(x) as xx approaches 3.
limx3h(x)=2 \lim_{x \rightarrow 3} h(x) = 2 228 2 \cdot 28 =56 = 56
The solution to the limit limx3(h(x)(2f(x)+3g(x)))\lim_{x \rightarrow 3}(h(x)(2 f(x)+3 g(x))) is 5656.

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