Math  /  Calculus

Question Find the rate of change of the area of a square as its sides increase at 6 m/sec6 \mathrm{~m} / \mathrm{sec}, when the sides are 20 m20 \mathrm{~m} and 26 m26 \mathrm{~m} long.

Studdy Solution
Calculate the rate of change of the area.
dAdt=×26 m/sec=312 m/sec\frac{dA}{dt} = \times26 \mathrm{~m^/sec} =312 \mathrm{~m^/sec}a. The area of the square is changing at a rate of 240 m/sec240 \mathrm{~m^/sec} when the sides are 20 m20 \mathrm{~m} long. b. The area of the square is changing at a rate of 312 m/sec312 \mathrm{~m^/sec} when the sides are 26 m26 \mathrm{~m} long.

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