Math  /  Trigonometry

QuestionProve that sec4θsec2θ=tan2θ+tan4θ\sec ^{4} \theta - \sec ^{2} \theta = \tan ^{2} \theta + \tan ^{4} \theta.

Studdy Solution
Now, we can see that the left side of the equation is equal to the right side of the equation.
tan2θ+tan4θtan2θ+tan4θ\tan ^{2} \theta + \tan ^{4} \theta \equiv \tan ^{2} \theta + \tan ^{4} \thetaHence, the given equation sec4θsec2θtan2θ+tan4θ\sec ^{4} \theta-\sec ^{2} \theta \equiv \tan ^{2} \theta+\tan ^{4} \theta is proved.

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord