Math  /  Calculus

Question Find the equation of a function f(x)f(x) whose range decreases in 1<x<1-1<x<1 and increases in x>1x>1 and x<1x<-1. A. f(x)=x22x+1f(x)=x^{2}-2x+1 B. f(x)=x2+2x+1f(x)=x^{2}+2x+1 C. f(x)=x3+3x+5f(x)=x^{3}+3x+5 D. f(x)=x33x+5f(x)=x^{3}-3x+5

Studdy Solution
Therefore, option D is the correct equation for f(x)f(x) because it satisfies the conditions that the range of f(x)f(x) decreases for 1<x<1-1 < x < 1 and increases for x>1x > 1 and x<1x < -1.
The correct answer is D. f(x)=x33x+5f(x) = x^3 - 3x + 5.

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