Math  /  Geometry

QuestionThe point (10,22)(-10,22) is on the terminal side of the angle and x=10,y=22x=-10, y=22. First find the value of rr. r=x2+y2=+484=\begin{aligned} r & =\sqrt{x^{2}+y^{2}} \\ & =\sqrt{ }+484 \\ & =\sqrt{ } \end{aligned}

Studdy Solution
Take the square root of the sum to find rr.
r=584 r = \sqrt{584}
Solution: The value of rr is 584\sqrt{584}, which simplifies to 21462\sqrt{146}.

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