QuestionCompare expected and experimental values for $i$ using osmotic pressure of $0.10 \mathrm{M}$ $\mathrm{Fe}\left(\mathrm{NH}_{4}\right)_{2}\left(\mathrm{SO}_{4}\right)_{2}$ at $25^{\circ} \mathrm{C}$, given $10.8 \mathrm{~atm}$.

Studdy Solution
Calculate the experimental $i$.
$$i = \frac{10.8 \, \mathrm{atm}}{0.10 \, \mathrm{M} \times0.0821 \, \mathrm{ \, atm/mol \, K} \times298.15 \, \mathrm{K}} =4.4$$The expected value for $i$ was5, but the experimental value was found to be4.4. This discrepancy could be due to the compound not fully dissociating in solution or due to interactions between the ions in solution.