Math  /  Algebra

QuestionFind the nnth term of the sequence: 198+(n+4)231198 + (n+4) \cdot 2^{31}.

Studdy Solution
Further simplify the expression.
an=198+(4+n)231a_n =198 + (4+n) \cdot2^{31}The nnth term of the sequence is 198+(4+n)231198 + (4+n) \cdot2^{31}.

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