Questionthe magnitude of its acceleration. A rocket sled accelerates at a rate of $49.0 \mathrm{~m} / \mathrm{s}^{2}$ . Its passenger has a mass of 75.0 kg . (a) Calculate the horizontal component of the force the seat exerts against his body. Compare this with his weight using a ratio. (b) Calculate the direction and magnitude of the total force the seat exerts against his body. Repeat the previous problem for a situation in which the rocket sled decelerates at a rate of $201 \mathrm{~m} / \mathrm{s}^{2}$ . In this problem, the forces are exerted by the seat and the seat belt. A body of mass 2.00 kg is pushed straight upward by a 25.0 N vertical force. What is its acceleration?

Studdy Solution
Calculate the acceleration of a body of mass $2.00 \, \mathrm{kg}$ pushed upward by a $25.0 \, \mathrm{N}$ force.
The net force acting on the body is the applied force minus the weight: $F_{\text{net}} = 25.0 - (2.00 \times 9.8) = 25.0 - 19.6 = 5.4 \, \mathrm{N}$
The acceleration $a$ is given by: $a = \frac{F_{\text{net}}}{m} = \frac{5.4}{2.00} = 2.7 \, \mathrm{m/s}^2$

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