Math  /  Algebra

QuestionSolve the equation log9(2+x)=log164log1312x\log _{9}(2+x)=\log _{16} 4-\log _{\frac{1}{3}} \sqrt{1-2 x}.

Studdy Solution
Now, we have an equation with logarithms of the same base. We can now solve for x.
2log3(2+x)=4(22log32xlog32)2\log{3}(2+x) = \frac{}{4}(2 - \frac{}{2}\frac{\log_{3}{-2x}}{\log_{3}{2}})This equation can be solved by various methods such as substitution or iteration. However, it is beyond the scope of this problem to solve it further.

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