QuestionSolve for $x$ in the equation $\log _{9}(2+x)=\log _{16} 4-\log _{1} \sqrt{1-2 x}$.

Studdy Solution
First, we simplify the right side of the equation. Notice that $\log{16}4 =1/2$ because $16^{1/2} =4$. And $\log{1} \sqrt{1-2 x}$ is undefined because the base of a logarithm cannot be1. Therefore, the original equation is incorrect.
$$\log{9}(2+x)=\log{16}4-\log{1} \sqrt{1-2 x}$$$$\log{9}(2+x)=1/2-\text{undefined}$$Since the equation contains an undefined term, it cannot be solved.