Math  /  Geometry

QuestionThe line in R3\mathbb{R}^{3} that is parallel to the yy-axis and passes through the point (1,2,3)(1,2,3) has equation [xyz]=+t\left[\begin{array}{l} x \\ y \\ z \end{array}\right]=\square+t \square
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Studdy Solution
The equation of the line is: [xyz]=[123]+t[010] \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} 1 \\ 2 \\ 3 \end{bmatrix} + t \begin{bmatrix} 0 \\ 1 \\ 0 \end{bmatrix}

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