Math  /  Calculus

QuestionEvaluate the integral e2θsin3θdθ\int e^{2 \theta} \sin 3 \theta d \theta.

Studdy Solution
implify the equation to get the final answer.
e2θsin3θdθ=313e2θcos3θ+213e2θsin3θ+C\int e^{2 \theta} \sin3 \theta d\theta = -\frac{3}{13}e^{2 \theta}\cos3 \theta + \frac{2}{13}e^{2 \theta}\sin3 \theta + CWhere C is the constant of integration.
So, the solution to the integral e2θsin3θdθ\int e^{2 \theta} \sin3 \theta d \theta is 313e2θcos3θ+213e2θsin3θ+C-\frac{3}{13}e^{2 \theta}\cos3 \theta + \frac{2}{13}e^{2 \theta}\sin3 \theta + C.

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