Math  /  Calculus

QuestionProjectile height is given by h(t)=16t2+256th(t)=-16 \cdot t^{2}+256 \cdot t. Find average velocity, speed, max height, and acceleration at t=5t=5.

Studdy Solution
So, the acceleration of the object at t=5t=5 is 32-32 feet per second squared.
The solutions are(a) The average velocity for the first3 seconds of travel is 192192 feet per second. (b) The velocity seconds after the projectile is thrown is 6464 feet per second and the height is 960960 feet. (c) The projectile reaches its maximum height of 10241024 feet at 88 seconds. (d) The acceleration of the object at t=5t=5 is 32-32 feet per second squared.

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