Math  /  Algebra

QuestionThe general solution is given for the system of linear equations. Find three individual solutions to the system. x+4y+2z=4x3yz=2x+yz=2\begin{array}{r} -x+4 y+2 z=4 \\ x-3 y-z=-2 \\ -x+y-z=-2 \end{array}
Solution: {(2z+4,z+2,z)z\{(-2 z+4,-z+2, z) \mid z is any real number }\}
Three possible solutions are \square . 1 \square \square ).( ■. \square ). and ([:-5). \square\square

Studdy Solution
Calculate the corresponding solutions.
The three individual solutions are:
1. (4,2,0)(4, 2, 0)
2. (2,1,1)(2, 1, 1)
3. (0,0,2)(0, 0, 2)

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