Math  /  Algebra

QuestionThe function f(x)=x+24x6f(x)=\frac{x+24}{x-6} is one-to-one. For the function, a. Find an equation for f1(x)f^{-1}(x), the inverse function. b. Verify that your equation is correct by showing that f(f1(x))=xf\left(f^{-1}(x)\right)=x and f1(f(x))=xf^{-1}(f(x))=x. a. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. (Simplify your answer. Use integers or fractions for any numbers in the expression.) A. f1(x)=f^{-1}(x)= \square , for x\mathrm{x} \neq \square B. f1(x)=f^{-1}(x)= \square , for xx \leq \square C. f1(x)=f^{-1}(x)= \square , for xx \geq \square D. f1(x)=f^{-1}(x)= \square , for all xx

Studdy Solution
Choose the correct option for the inverse function:
The inverse function is valid for all x1 x \neq 1 because the denominator in f1(x) f^{-1}(x) cannot be zero. Thus, the correct choice is:
A. f1(x)=6x+24x1 f^{-1}(x) = \frac{6x + 24}{x - 1} , for x1 x \neq 1
The inverse function is:
6x+24x1 \boxed{\frac{6x + 24}{x - 1}}

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