Math  /  Calculus

QuestionThe function f(x)=2x333x2+168x10f(x)=2 x^{3}-33 x^{2}+168 x-10 has two critical numbers.
Give the two critical numbers as a commaseparated list. x=x= \square

Studdy Solution
Verify the solutions by substituting back into the derivative to ensure they make it zero:
For x=4 x = 4 : f(4)=6(4)266(4)+168=0 f'(4) = 6(4)^2 - 66(4) + 168 = 0
For x=7 x = 7 : f(7)=6(7)266(7)+168=0 f'(7) = 6(7)^2 - 66(7) + 168 = 0
Both solutions satisfy the equation.
The two critical numbers are:
4,7 \boxed{4, 7}

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