Math  /  Algebra

QuestionThe following formulas give animal populations as functions of time, tt, in years. Describe the growth of each population in words. (a) P=1200+300tP=1200+300 t
The population is \square .
Its initial value is ii
The change is happening at \square (b) P=270080tP=2700-80 t
The population is \square .
Its initial value is \square \square .
The change is happening at \square (c) P=1700(1.03)tP=1700(1.03)^{t}
The population is \square .
Its initial value is \square .
The change is happening at \square of \square

Studdy Solution
(a) The population is **increasing**.
Its initial value is **1200**.
The change is happening at a rate of **300 per year**.
(b) The population is **decreasing**.
Its initial value is **2700**.
The change is happening at a rate of **80 per year**.
(c) The population is **increasing**.
Its initial value is **1700**.
The change is happening at a rate of **3% per year**.

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord